Multiwfn official website: //www.umsyar.com/multiwfn. Multiwfn forum in Chinese: http://bbs.keinsci.com/wfn
You are not logged in.
Hello,
I have carried out the second order perturbation analysis and a small section of the output is (showing the involved NBOs and Stabilization Energies):
21. BD(1) C 25-H 28 /121. LP*(7)Fe 30 9.06
21. BD(1) C 25-H 28 /122. LP*(8)Fe 30 11.23
Now NBO No. 121 and 122 are almost pure P orbitals as can be seen from below
121. (0.09383) LP*(7)Fe 30 s(1.96%)p49.61(97.4%)d 0.30(0.60%)f 0.00(0.00%)
122. (0.08905) LP*(8)Fe 30 s(1.16%)p84.81(98.31%)d 0.46(0.53%)f 0.00(0.00%)
My question is which of the two NBO(121 or 122 or both) should I consider? Do I need to add both values of stabilization energies (11.23+9.06) to make comparison with other systems?
Regards,
Anjali
Offline
Dear Anjali,
Both of them should be considered. However, the two values cannot be added together, there will be an overcounting problem.
Best,
Tian
Offline
Then how am I supposed to make comparison with other system since the other system also has a stabilization energy of 18.87 and 0.80 respectively for the same donor-acceptor pairs.
Added to this there are contributions involving s-orbital.
Here am giving an example of how the systems differ in their stabilization energy values.
System 1
donor-->p-orbital = 11.23
donor-->p-orbital = 9.06
donor-->s-orbital= 4.83
System2
donor-->p-orbital = 18.87
donor-->p-orbital = 0.80
donor-->s-orbital= 15.06
The donor orbital is the same in each case. It is a C-H sigma bond.
Last edited by Anjali Ganai (2023-06-15 11:43:02)
Offline
Thanks a lot.
Regards,
Anjali
Offline