Multiwfn forum

Hello.
Using Multiwfn it is possible to get transparent images by setting itransparent=1 in settings.ini.
I am wondering if it is possible to get transparent images using the VMD program.
For example, to the left of the attached image is an image with transparency obtained with Multiwfn, and to the right is an image obtained with VMD.
I can't find a way to get an image with transparency using VMD. Could you tell me if this is possible?

I want to perform the topological analysis of the electron density difference (for example, of the water molecule). I previously placed the .wfn files in the Multiwfn directory as indicated in the manual, the steps I performed are as follows:
I execute the file water.fch in Multiwfn
iu //
-1 // I'm not sure here if I should use this option or the user-defined option "-3", then I continue:
5// data grid
-2// deformation property
1// electron density
3// high quality grid
0// return
2// topology analysis
-11// select function
100// user-defined function
6//
11// points in the sphere
6000//
-1// each nucleus in turn
-9// return
-10// return main menu

Then with the main option "13" I visualize the CPs and the isosurface (see Fig. 1). My question is whether this sequence of steps is correct for this type of analysis since the poincare-hopf relationship is not satisfied.

Using a VMD script written by me (IGMinter_isoall.tcl) I try to visualize the behavior of dginter in the course of a reaction (Fig. 1), but the VMD script does not work correctly. Could you check the IGMinter_isoall.tcl script and correct it?
I wrote the IGMinter_isoall.tcl script according to what is indicated in section 4.20.10.2 of the Multiwfn Manual
In RG I attach the files if necessary:

https://www.researchgate.net/post/Tcl_script_in_VMD

---IGMinter_isoall.tcl------------------------------------------------------------------------------------------------

set nsystem 51

set isovaldginter 0.01
set colordginter 7

set colorlow -5.0
set colorhigh 5.0

for {set i 1} {$i<=$nsystem} {incr i} {
set name SP[format %04d $i]
puts "Processing atmdg_$name.pdb and dg_inter_$name.cub..."

display projection Orthographic
display rendermode GLSL
display depthcue off
light 2 on
light 3 on

color Display Background white
axes location Off

color scale method BWR
mol default style CPK

mol new atmdg_$name.pdb
mol new dg_inter_$name.cub

mol modstyle 0 top CPK 1.0 0.8 18.0 16.0
mol modcolor 0 top Beta
mol modmaterial 0 top EdgyShiny
mol scaleminmax 0 top $colorlow $colorhigh

mol modstyle 0 1 Isosurface $isovaldginter 0 0 0 1 1
mol modcolor 0 1 ColorID $colordginter
mol modmaterial 0 1 EdgyGlass

render snapshot $name.bmp

mol delete top
mol delete top
}

I want to perform a RELAXED SCAN calculation between 12-crown-4 and lithium cation in Gaussian 9 consisting of the following:
As a starting point, placing the Li+ at a distance of 0.4 Å from the center of 12-crown-4 to a distance of 5.4 Å from said center as the end point of the calculation, with 0.4 Å increments (Fig. 1).
In other words, I want to perform the relaxed scan calculation by placing the Li+ at a slightly different distance from the center of the 12-crown-4 (this for symmetry reasons, to avoid a reorientation of the molecular system in the course of the calculation) up to a distance farthest from the ring. The problem I have is that I don't know how to type or what keywords should I use in Gaussian 9's .gjf file to run this calculation.
I attach the optimized geometry at the hf/3-21g level in salt.gjf (it is D2d symmetry).

%chk=C:\salt.chk
# hf/3-21g

Title Card Required

1 1
Li                 0.00000000    0.00000000    0.00000000
O                  1.80378214   -0.00000000    0.32927408
C                  2.30761918    1.26176110   -0.19253296
C                  2.30761918   -1.26176110   -0.19253296
C                  1.26176110    2.30761918    0.19253296
C                  1.26176110   -2.30761918    0.19253296
O                  0.00000000    1.80378214   -0.32927408
O                 -0.00000000   -1.80378214   -0.32927408
C                 -1.26176110    2.30761918    0.19253296
C                 -1.26176110   -2.30761918    0.19253296
C                 -2.30761918    1.26176110   -0.19253296
C                 -2.30761918   -1.26176110   -0.19253296
O                 -1.80378214   -0.00000000    0.32927408
H                  3.26664225    1.49572411    0.24426407
H                  2.39390318    1.19789109   -1.26923404
H                  3.26664225   -1.49572411    0.24426407
H                  2.39390318   -1.19789109   -1.26923404
H                  1.49572411    3.26664225   -0.24426407
H                  1.19789109    2.39390318    1.26923404
H                  1.49572411   -3.26664225   -0.24426407
H                  1.19789109   -2.39390318    1.26923404
H                 -1.49572411    3.26664225   -0.24426407
H                 -1.19789109    2.39390318    1.26923404
H                 -1.49572411   -3.26664225   -0.24426407
H                 -1.19789109   -2.39390318    1.26923404
H                 -3.26664225    1.49572411    0.24426407
H                 -2.39390318    1.19789109   -1.26923404
H                 -3.26664225   -1.49572411    0.24426407
H                 -2.39390318   -1.19789109   -1.26923404

I also asked this question in researchgate but I can't find an answer:

https://www.researchgate.net/post/How_t … aussian_09